EASY
CISF Head Constable
IMPORTANT
Earn 100

Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3 : 4. Find A’s present age.

50% studentsanswered this correctly

Important Questions on Arithmetic Maths

EASY
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 16
3 years ago a father's age was twice the sum of ages of his 4 sons. In next 3 years from present, the father's age will be equal to sum of ages of the sons. Find the present age of father?
EASY
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 17
At the time of marriage, a man was 6 years elder to his wife. 12 years after their marriage his age is 65 times the age of his wife. What was wife's age the time of marriage?
EASY
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 18
The ages of A and B are in the ratio 8 : 5. If the sum of their ages in 39 years, what will be the ratio of their ages after 9 years?
EASY
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 19
Present ages of A and B are 50 years and 18 years respectively. In how many years will A be twice as old as B.
EASY
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 20
Ratio between present ages of A and B is 3 : 4. What is the present age of A, if 4 years ago the ratio was 5 : 7?
EASY
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 21
A man is 24 years older than his son, In two years, his age will be twice the age of his son. The present age of the son is:
MEDIUM
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 22
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
EASY
CISF Head Constable
IMPORTANT
Police Constables>Chapter 3 - Arithmetic Maths>PROBLEMS ON AGES>Q 23
The sum of the present ages of a father and his son os 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be: