Suppose $1 \mathrm{mL}$ of a ${\mathrm{KMnO}}_4$ solution reacts with $0.140 \mathrm{g} {\mathrm{Fe}}^{2+}$. If $1 \mathrm{mL}$ of ${\mathrm{KHC}}_2{\mathrm{O}}_4.{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4$ solution reacts with $0.1 \mathrm{mL}$ of the previous ${\mathrm{KMnO}}_4$ solution, how many millilitres of $0.20 \mathrm{M}$ $\mathrm{NaOH}$ will react with $1 \mathrm{mL}$ of the ${\mathrm{KHC}}_2{\mathrm{O}}_4.{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4$ solution mentioned above, in which all the protons $\left({\mathrm{H}}^{+}\right)$ are ionisable?

What is the volume of $3 \mathrm{M} \mathrm{Ba}(\mathrm{OH}{)}_2$ solution required to neutralize completely $120 \mathrm{mL}$ of $1.5 \mathrm{M} {\mathrm{H}}_3{\mathrm{PO}}_4$ solution?

When tetracarbonylnickel $\left(0\right)$ is heated, it dissociates into its components. If $5$ moles of this compound is heated and the resulting gaseous component is absorbed by sufficient amount of ${\mathrm{I}}_2{\mathrm{O}}_5$, liberating ${\mathrm{I}}_2$. What volume of $4\mathrm{M}$ Hypo solution will be required to react with this ${\mathrm{I}}_2$?

$\mathrm{Ni}{\left(\mathrm{CO}\right)}_4 \stackrel{∆}{\to } \mathrm{Ni} + 4\mathrm{CO}$

$1$ mole of ${\mathrm{OH}}^{-}$ is obtained from $85 \mathrm{g}$ of hydroxide of a metal. What is the equivalent weight of the metal?

An oxide of a metal contains $40\%$ oxygen, by weight. What is the equivalent weight of the metal?

In the following reaction, $3\mathrm{Fe}+4{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{Fe}}_3{\mathrm{O}}_4+4{\mathrm{H}}_2,$ if the atomic weight of iron is $56$, then what will be its equivalent weight?

Potassium acid oxalate ${\mathrm{K}}_2{\mathrm{C}}_2{\mathrm{O}}_4.3{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4.4{\mathrm{H}}_2\mathrm{O}$ can be oxidized by ${\mathrm{MnO}}_4^{-}$ in acid medium. Calculate the voluem of $(\mathrm{in} \mathrm{mL}) 1 \mathrm{M} {\mathrm{KMnO}}_4$ reacting in acid solution with $5.08$ gram of the acid oxalate.

In the following reaction, ${\mathrm{SO}}_2$ acts as a reducing agent:

${\mathrm{SO}}_2+{\mathrm{Cl}}_2+2{\mathrm{H}}_2\mathrm{O} \stackrel{ }{\to } {\mathrm{H}}_2{\mathrm{SO}}_4+2\mathrm{HCl}$

Find the equivalent weight of ${\mathrm{SO}}_2$.