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Suppose a1,a2,2,a3,a4 be in an arithmetico-geometric progression. If the common ratio of the corresponding geometric progression is 2 and the sum of all 5 terms of the arithmetico-geometric progression is 492, then a4 is equal to ______________

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Important Questions on Sequences and Series

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If 2019+2212018+32122017+...+202119=k2019, then k is equal to _____.

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If the value of 1+23+632+1033+.. upto log0.2513+132+133+. upto  is l, then l2 is equal to             .

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Let a1,a2,a3, be an A.P. If r=1ar2r=4, then 4a2 is equal to ______.
EASY
If b is the first term of an infinite geometric progression whose sum is five, then b lies in the interval 
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The sum of the infinite series 1+23+732+1233+1734+2235+ is equal to:
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For kN, if the sum of the series 1+4k+8k2+13k3+19k4+...... is 10, then the value of k is

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If S=75+952+1353+1954+, then 160 S is equal to                   .
HARD
Let bi>1 for i=1, 2,.,101. Suppose logeb1,logeb2,..,logeb101 are in Arithmetic Progression (A.P.) with the common difference loge2.  Suppose a1, a2,.,a101 are in A.P. such that a1=b1 and a51=b51. If t=b1+b2++b51 and s=a1+a2++a51, then
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The sum of the series 1372.2.1+1973.3.2+2574.4.3+.... up to infinity is
HARD
Let S=2+67+1272+2073+3074+.. then 4S is equal to
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The sum of the first 10 terms of the series 9+99+999+.. is
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The sum k=120k12k is equal to
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If a, b and c be three distinct real numbers in G.P. and a+b+c=xb, then x cannot be:
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Let S=109+1085+10752+.+25107+15108. Then the value of 16S-(25)-54 is equal to
HARD

If m is the A.M. of two distinct real numbers I and n I, n>1  and G1, G2 and G3 are three geometric means between I and n, then G14+2G24+G34 equals

EASY
The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P., then the sum of the original three terms of the given G.P. is :
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Let a, b and c be the 7th, 11th and 13th terms respectively of a non-constant A.P. If these are also the three consecutive terms of a G.P., then ac is equal to:
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The sum 1+2·3+3·32+..+10·39 is equal to
HARD
The sum of the series 121·2+12+222·3+12+22+323·4+  upto 20 terms is
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If (10)9+2(11)1(10)8+3(11)2(10)7+......+10(11)9 =k(10)9, then k is equal to :