Taking $13$ years as assumed mean, find the mean from the following distribution table.

Number of friends	$6$	$12$	$19$	$10$	$15$	$29$	$26$	$23$	$17$	$11$	$8$	$6$	$5$
Age (in years)	$8$	$9$	$10$	$11$	$12$	$13$	$14$	$15$	$16$	$17$	$18$	$19$	$20$

For the given data:

The median is _____.

In a class of $40$ students, marks obtained by the students in a class test (out of $10$) are given below:

Calculate the Median for the given distribution.

Find the median of the following data:

$45, 41, 43, 38, 40, 42, 44$

The mean of the data $x_1, x_2, x_3 \dots \dots x_{10}$ is $20$ then the mean of $x_1+ 4, x_2+ 4, x_3+ 4, \dots \dots \dots . x_{10}+ 4$ will be 

What is the median of the following list of numbers?

$5, 3, 6, 9, 11, 19$ and $1$

What is the mode of the given data?

$4, 3, 7, 13, 16, 23, 3, 4, 7, 4, 3, 3, 9, 6, 9, 6$

The following is the price of Cabbage over 12 months. What is the median price?

Find the mean of distribution if its median and mode are $45 \& 13$ respectively.

The mean of a frequency distribution is $8.1$ if $\sum _{}{f}_i{x}_i=132+5k$ and $\sum _{}{f}_i=20$ then what is the value of $k$?

The variables $x_1, x_2, \dots .. x_{100}$ are in ascending order of their magnitude, then the median of the variables is then the median of the variables is $\frac{(x_k+x_{51}+1)}{2}$. then the value of$k$ is _____.

The mean and median of  $7, 5, 5, 2, 7, 6, 5, 3, 7, 6$is-

1. $5.3$ and $5$

2. $5$ and $5.5$

3. $5$ and $6$

4. $5.3$ and $5.5$