The L.C.M. of $87$ and $145$ is _____ .

Important Questions on Number System

MEDIUM

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 8

A person has three iron bars whose lengths are $10 m, 15 m \& 20 m$ respectively. He wants to cut pieces of same length from each of the three bars. What is the least number of total pieces, if he is to cut without any wastage? 

EASY

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 9

LCM of  $\frac{3}{2},\frac{9}{4},\frac{6}{16},$ and $\frac{12}{32}$ is:

EASY

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 10

Find the GCD of $42,63$ and $140$.

EASY

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 11

Find the largest number of $5$ digits which when divided by $3, 5, 8, 12$ leaves the same remainder $2$ in each case.

MEDIUM

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 12

The sum of two numbers is $462$ and their highest common factor is $22$. What is the maximum number of pairs that satisfy these conditions?

EASY

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 13

There are $4$ numbers. The GCD of each pair is $3$ and the LCM of all the $4$ numbers is $116$. What is the product of $4$ numbers?

EASY

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 14

Let N be the greatest number that will divide $1305$, $4665$, and $6905$, leaving the same remainder in each case. Then the sum of the digits in N is:

EASY

SRMJEEE (UG)

IMPORTANT

Practice book for English and Aptitude for SRMJEEE (UG)>Chapter 1 - Number System>LCM and GCD>Q 15

Find the greatest number that will divide $43, 91$, and $183$ so as to leave the same remainder in each case.