The Lyman series corresponds to the emission lines of hydrogen atom due to the transitions of the type n → 1 ( 2 → 1 , 3 → 1 , 4 → 1 , etc ) where n is the principal quantum number of the excited state. The ionization energy of the hydrogen atom can be determined by plotting:

Frequency differences between successive emission lines vs emission frequencies

Frequency differences between successive emission lines vs n

The Lyman series corresponds to the emission lines of hydrogen atom due to the transitions of the type n → 1 ( 2 → 1 , 3 → 1 , 4 → 1 , etc ) where n is the principal quantum number of the excited state. The ionization energy of the hydrogen atom can be determined by plotting:

Frequency differences between successive emission lines vs emission frequencies

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The Lyman series corresponds to the emission lines of hydrogen atom due to the transitions of the type $n \to 1 (2 \to 1, 3 \to 1, 4 \to 1$ , etc ) where $n$ is the principal quantum number of the excited state. The ionization energy of the hydrogen atom can be determined by plotting:

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Important Questions on Structure of Atom

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

Which of the following statements is false?

EASY

Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The number of following statement/s which is/are incorrect is ______

A) Line emission spectra are used to study the electronic structure

B) The emission spectra of atoms in the gas phase show a continuous spread of wavelength from red to violet.

C) An absorption spectrum is like the photographic negative of an emission spectrum

D) The element helium was discovered in the sun by spectroscopic method

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

For any given series of spectral lines of atomic hydrogen, let $Δ \bar{v} = {\bar{v}}_{m a x} - {\bar{v}}_{m i n}$ be the difference in maximum and minimum wave number in $c m^{- 1}$ .

The ratio $Δ {\bar{v}}_{L y m a n} / Δ {\bar{v}}_{B a l m a r}$ is

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

For the Balmer series, in the spectrum of

H

atom,

\bar{v} = R_{H} \{\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}\},

the correct statements among

(I)

(I V)

are,

(I)

As wavelength decreases, the lines in the series converge.

(I I)

The integer

n_{1}

is equal to

2

(I I I)

The lines of the longest wavelength correspond to

n_{2} = 3

(I V)

The ionization energy of hydrogen can be calculated from the wave number of these lines.

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The spectrum of Helium is expected to be similar to that of____

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about

9

. The spectral series are:

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

If the shortest wavelength in Lyman series of hydrogen atom is

A

, then the longest wavelength in Paschen series of

{He}^{+}

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

If the wave number of first spectral line of Lyman series of

{He}^{+}

{Xcm}^{- 1}

, then the wave number of second line of Balmer series of hydrogen atom in

{cm}^{- 1}

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The product obtained after positron emission from

{}_{31}{Ga}^{68}

EASY

Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

Which one of the following has the highest wavelength?

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The shortest wavelength of

H

atom in the Lyman series is

λ_{1}

. The longest wavelength in the Balmer series of

{He}^{+}

is :

EASY

Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

78) There are two statements, one labelled as Assertion (A) and the other as Reason (R). Examine both the statements carefully and mark the correct choice.
(A) Hydrogen has one electron in its orbit but it produces several spectral lines.
(R) There are many excited energy levels available.

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The region in the electromagnetic spectrum where the Balmer series lines appear is:

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

Which of the following series of transitions in the spectrum of hydrogen atom falls in visible region?

EASY

Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

Two series of spectral lines of atomic hydrogen which do not belong to infrared spectral region are

EASY

Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

With respect to atomic spectrum, each line in the Lyman series is due to electrons returning

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

If the wavelength of an electronic transition in

{He}^{+}

23 nm

, the wavelength corresponding to same transition in hydrogen atom in

nm

EASY

Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

Which of the following is correct?

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Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The ratio of the highest to the lowest wavelength of Lyman series is

HARD

Chemistry>Physical Chemistry>Structure of Atom>Atomic Spectra

The correct representation of wavelength intensity relationship of an ideal black body radiation at two different temperatures

T_{1}

and

T_{2}

The Lyman series corresponds to the emission lines of hydrogen atom due to the transitions of the type n→1(2→1,3→1,4→1, etc ) where n is the principal quantum number of the excited state. The ionization energy of the hydrogen atom can be determined by plotting:

Important Questions on Structure of Atom

Learn and Prepare for any exam you want !

The Lyman series corresponds to the emission lines of hydrogen atom due to the transitions of the type $n \to 1 (2 \to 1, 3 \to 1, 4 \to 1$ , etc ) where $n$ is the principal quantum number of the excited state. The ionization energy of the hydrogen atom can be determined by plotting: