The $\mathrm{X}-\mathrm{X}$ bond dissociation energy is minimum in:

${\mathrm{F}}_2+\text{dil. }\mathrm{NaOH}⟶\mathrm{A}+\mathrm{NaF}+{\mathrm{H}}_2\mathrm{O}$

${\mathrm{F}}_2+\text{conc.} \mathrm{NaOH}⟶\mathrm{B}+\mathrm{NaF}+{\mathrm{H}}_2\mathrm{O}$

$\mathrm{A}$ and $\mathrm{B}$ respectively are:

${\mathrm{NH}}_3\left(\mathrm{excess}\right)+{\mathrm{Cl}}_2⟶{\mathrm{NH}}_4\mathrm{Cl}+\mathrm{A}\left(\mathrm{gas}\right)$

${\mathrm{NH}}_3+{\mathrm{Cl}}_2\left(\mathrm{excess}\right)⟶\mathrm{B}+\mathrm{HCl}$

Incorrect statement regarding $\mathrm{A}$ and $\mathrm{B}$.

${\mathrm{\Delta H}}_{\mathrm{vaporisation} }(\mathrm{KJ} {\mathrm{mol}}^{-1})$ are given for the hydrides of halogens in the following graph. The hydride $\mathrm{HF}$ will correspond to-