The adjoining figure is made of two squares whose sides are $2 cm$ and $6 cm$ respectively. So, the perimeter of the figure will be:

A painting is 80 cm wide and 1.6 m long. The ratio of its length to its perimeter in the simplest form is:

If the length of a rectangle becomes half and breadth of a rectangle becomes double, then the area of the rectangle:

Find the perimeter of rectangle, if the area of a rectangle is $660 c{m}^2$ and breadth is $20 m$.

Determine the perimeter of the following figure:

Determine the perimeter of the following figure:

Find the area of the following figure:

Find the area of the following figure:

Find the area of the figures, assuming the side of each square is $1 cm$