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The amplitude of the wave resulting from the superposition of three waves given by x1=Acosωt, x2=2Asinωt and x3=2Acosωt+π4 is

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Important Questions on Simple Harmonic Motion

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A simple harmonic oscillator of frequency 1 Hz has a phase of 1 radian. By how much should the origin be shifted in time so as to make the phase of the oscillator vanish. (time in seconds).
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A particle of mass 0.1 kg is executing simple harmonic motion of amplitude 0.1 m. When the particle passes through the mean position, its kinetic energy is 8×10-3 J. If the initial phase is 45°, the equation of its motion is (Assume, x t as the position of the particle at time t)
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Which of the following equation represents a simple harmonic motion? (ω is angular frequency, A is amplitude of oscillation and i=-1)
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A particle is executing simple harmonic motion (S.H.M.). Its acceleration at a distance of 1 cm from the mean position is 3 cm s-2. If its velocity is 6 cm s-1 when it is at a distance of 2 cm from its mean position, then the amplitude of S.H.M. is, 
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A simple harmonic oscillator has an amplitude of 0.5 m and a time period of 2 seconds. What is the magnitude of acceleration when it is displaced from the mean position by 0.25 m?
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A body of mass 1 kg is executing simple harmonic motion (SHM). Its displacement y (in cm) at time t given by y=6sin100t+π4cm. Its maximum kinetic energy is
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The displacement of a particle in simple harmonic motion (SHM) is given by y=3πsin100πt+π4. What will be the displacement of the particle from the mean position when its kinetic energy is eight times that of its potential energy?
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A particle of mass m is attached to four springs with spring constant k,k,2k and 2k as shown in the figure. Four springs are attached to the four corners of a square and a particle is placed at the center. If the particle is pushed slightly towards any side of the square and released, the period of oscillation will be

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