The angle measuring $270°$​ when expressed in centesimal system is:

Read the given question and decide which of the following information is sufficient to answer the question.

What is the value of 0?

Information :

(II) 0 < q < 90°

In the given diagram, point R and Q are on PS. ÐPQT = x°, ÐRQT = (x – 50)° and ÐTUR = (x + 25°). find the value of ÐURS.

In $△\mathrm{ABC},$ if $\mathrm{AB}=\mathrm{AC}$ and $\angle \mathrm{BAC}={40}^{\circ }$, then the measure of $\angle \mathrm{B}$ is:

Let $P=(\theta :\sin \theta -\cos \theta =\sqrt{2}\cos \theta \}$ and $Q=\{\theta :\sin \theta +\cos \theta =\sqrt{2}\sin \theta \}$ be two sets. Then,

Solve the following.

$\frac{\sin {40}^{\mathrm{o}}}{\cos {50}^{\mathrm{o}}}+\frac{\mathrm{cosec} {50}^{\mathrm{o}}}{\sec {40}^{\mathrm{o}}}-4\cos {50}^{\mathrm{o}} \mathrm{cosec} {40}^{\mathrm{o}}$

 Study the following question and decide that which of the following information is sufficient to answer the question? What is the value of $\angle \mathrm{ACB}$ ?

Information:

1. 

2.$\angle D={60}^0$