The angular width of the central maximum of a diffraction pattern of a single slit pattern is $60°,$ the slit width being $1\mathrm{\mu m}$. A double slit experiment is now performed with the same wavelength of light and the same slit widths and it is found that the ${10}^{\text{th }}$ interference maximum is not formed, but all lower maxima are visible. The separation between the double slits is

Diffraction pattern from a single slit is shown in the figure. The point at which the path difference between two extreme rays from the slit is twice the wavelength is given by the point

A diffraction pattern obtained from a double slit illuminated with monochromatic light is shown in the figure. The dotted line in the figure shows the diffraction envelope while the solid lines give the double slit interference fringes. The experimenter has an arrangement to keep the separation between the slits $\left(d\right)$ fixed, but varies the width of the slits$\left(a\right)$. The intensities of the peaks marked by$1$ and$2$ are $I_1$ and $I_2$ respectively. If the slits are made narrower while keeping the separation fixed, then the ratio $\frac{I_2}{ I_1}$

When the frequency of the light used is changed from $4\times {10}^{14} {\mathrm{s}}^{-1}$ to $5\times {10}^{14} {\mathrm{s}}^{-1}$, the angular width of the principal (central) maximum in a single slit Fraunhofer diffraction pattern changes by $0.6$ radian. What is the width of the slit (assume that the experiment is performed in vacuum)?

In the Fraunhofer diffraction experiment, the first minima of red light ($660 \mathrm{nm}$) is formed at the first maxima of another light of wavelength $\lambda \text{'}$. Find the value of $\mathrm{\lambda }\text{'}$.

Draw a labelled graph of the intensity of diffracted light $\left(I\right)$ versus angle$\left(\theta \right)$ in the Fraunhofer diffraction experiment for a single-slit diffraction.