Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 31

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The best reagent to convert pent- $3$ -en- $2$ -ol into pent- $3$ -en- $2$ -one is:

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Important Questions on Hydrocarbon (Alkane, Alkene & Alkyne)

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 32

Which of the following reactions will yield

2, 2

- dibromopropane?

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 33

In the following sequence of reactions, the alkene affords the compound

' B'

{CH}_{3} CH = {CHCH}_{3} \overset{O_{3}}{⟶} A \frac{H_{2} O}{Zn} ⟶ B,

the compound

B

is

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 34

The hydrocarbon which can react with sodium in liquid ammonia is:

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 35

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of

44 u .

The alkene is:

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 36

Ozonolysis of an organic compound gives formaldehyde as one of the products. This confirms the presence of:

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 37

In the compound

{CH}_{2} = CH - {CH}_{2} - {CH}_{2} - C \equiv CH

, the

C_{2} - C_{3}

bond is of the type:

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 38

The product(s) via-oxymercuration

({HgSO}_{4} + H_{2} {SO}_{4})

of

1

-butyne would be:

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Practice Book for KVPY Aptitude Test - Stream SA Chemistry>Chapter 13 - Hydrocarbon (Alkane, Alkene & Alkyne)>EXERCISE>Q 39

Propyne and propene can be distinguished by: