The circuit shown in the figure consist of a battery of emf $\epsilon =10\mathrm{V}$; a capacitor of capacitance $C=1.0\mu \mathrm{F}$ and three resistor of values $R_1=2\mathrm{\Omega }, R_2=2\mathrm{\Omega }$ and $R_3=1\mathrm{\Omega }$. Initially the capacitor is completely uncharged and the switch $S$ is open. The switch $S$ is closed at $t=0$.

 

In the circuit shown, the cell is ideal, with emf $15\mathrm{V}$. Each resistance is of $3\mathrm{\Omega }$. The potential difference across the capacitor is

In the circuit shown $E,F,G$ and $H$ are cells of e.m.f. $2 \mathrm{V},1 \mathrm{V},3 \mathrm{V}$ and $1 \mathrm{V}$ respectively and their internal resistances are $2\Omega ,1\Omega ,3\Omega$ and $1\Omega$ respectively then

 Consider the circuit shown in the figure

In the circuit shown in figure -