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The circular motion of a particle with constant speed is

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Important Questions on Simple Harmonic Motion

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If the differential equation for a simple harmonic motion is d2ydt2+2y=0, the time period of the motion is,
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The radius of circle, the period of revolution, initial position and sense of revolution are indicated in the figure.
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y-projection of the radius vector of rotating particle P is
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A body of mass 1 kg is executing simple harmonic motion. Its displacement ycm at t seconds is given by y=6sin100t+π4. Its maximum kinetic energy is

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A particle of mass 0.1 kg is executing simple harmonic motion of amplitude 0.1 m. When the particle passes through the mean position, its kinetic energy is 8×10-3 J. If the initial phase is 45°, the equation of its motion is (Assume, x t as the position of the particle at time t)
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A particle is executing a simple harmonic motion. Its maximum acceleration is α and maximum velocity is β. Then, its time period of vibration will be:
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A simple pendulum oscillates harmonically about x=0 with an amplitude A and time period T. Its speed at x=A/2 is
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The oscillation of a body on a smooth horizontal surface is represented by the equation, X=Acosωt, where X= displacement at time tω=  frequency of oscillation, a= acceleration at time t and T= time period.
Which one of the following graph shows correctly the variation a with t ?
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In the case of a simple pendulum executing SHM, at t=0, the bob is not at the mean position. The graph drawn between the tension T in the string and time t is
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A simple pendulum of length L has mass M and it oscillates freely with amplitude A. At the extreme position, its potential energy is (g = acceleration due to gravity)
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A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
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Which of the following equation represents a simple harmonic motion? (ω is angular frequency, A is amplitude of oscillation and i=-1)
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A particle is executing SHM along a straight line. Its velocities at distances x1 and x2 from the mean position are V1 and V2 respectively. Its time period is:
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A particle performs S.H.M. with amplitude A. Its speed is tripled at the instant when it is at a distance of 2A3 from the mean position. The new amplitude of the motion is
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If x, v and a denote the displacement, the velocity and the acceleration of a particle executing SHM of time period T. Then, which of the following does not change with time?
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A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes S.H.M. of period T. If the mass is increased by m, the time period becomes 5T3. What is the ratio Mm?
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Y=Asinωt+ϕ0 is the time-displacement equation of a SHM. At t=0 the displacement of the particle is Y=A2 and it is moving along negative x-direction. Then the initial phase angle ϕ0 will be:
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The physical quantity conserved in simple harmonic motion is
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A body is in simple harmonic motion with time period   T=0.5s and amplitude A=1cm . Find the average velocity in the interval in which it moves from equilibrium position to half of its amplitude.
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A particle is performing SHM starting from extreme position. Graphical representation shows that, between displacement and acceleration, there is a phase difference of
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Which of the following plots represents schematically the dependence of the time period of a pendulum if measured and plotted as a function of its oscillations? (Note: amplitude need not be small)