The compound in which carbon atom uses only its ${\mathrm{sp}}^3$ hybrid orbitals for bond formation is:

Three molecules $\mathrm{X}, \mathrm{Y}$ and $\mathrm{Z}$  have $\%$ of $\mathrm{s}-$character in orbitals of the central atom in the order $\mathrm{Y}>\mathrm{Z}>\mathrm{X}$.

Determine the order of $\%$ of $\mathrm{p}-$character in orbitals of central atoms of $\mathrm{X}, \mathrm{Y}$ and $\mathrm{Z}$.

NOTE: Assume that the hybrid orbitals in all the three molecules are made up of only $\mathrm{s}$ and $\mathrm{p}$ orbitals.