MEDIUM
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The continuous random variable X represents the amount of sunshine in hours between noon and 4 pm at a skiing resort in the high season. The probability density function, f(x), of X is modelled by f(x)=3x264     for 0x40     otherwise . Find P(2<x<4).

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Important Questions on Continuous Random Variables

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A random variable X takes the values 0,1,2. Its mean is 1.2 if PX=0=0.3, then PX=1= 
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For the following probability distribution:

X 1 2 3 4
PX 110 15 310 25

EX2 is equal to

HARD
Let X be a random variable which takes values k with the probability kp, where k=1, 2, 3, 4 and p(0,1), then the standard deviation of X is
EASY

Given below is the probability distribution of discrete random variable X

X=x 1 2 3 4 5 6
PX=x K 0 2K 5K K 3K

Then, PX4=

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An unbiased coin is tossed 5 times. Suppose that a variable X is assigned the value k when k consecutive heads are obtained for k=3,4,5, otherwise X takes the value -1. Then the expected value of X, is
HARD
Suppose A is 3×3 matrix consisting of integer entries that are chosen at random from the set -1000,-999,999,1000. Let P be the probability that either A2=-I or A is diagonal, where I is the 3×3 identity matrix. Then,
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Let xi1i10 be ten observation of a random variable X. If i=110xi-p=3 and i=110xi-p2=9 where 0pR, then the standard deviation of these observations is:
 
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What is the mean of fx=3x+2 where x is a random variable with probability distribution

X=x 1 2 3 4
PX=x 16 13 13 16
EASY
A random variable X has the following probability distribution:
X:12345PX: k22kk2k5k2
Then, PX>2 is equal to:
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A random variable X has the following probability distribution

X 1 2 3 4 5 6 7
P(X) K-1 3K K 3K 3K2 K2 K2+K
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For the probability distribution given by

X=xi 0 1 2
Pi 25/36 5/18 1/36

The standard deviation σ is

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A box contains 6 pens, 2 of which are defective. Two pens are taken randomly from the box. If random variable x: Number of defective pens obtained, then standard deviation of x=
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The probability distribution of a discrete random variable X is given in the following table:

X=x 0 1 2
Px 4C3 4C-13C2 7C-1

C>0 then C=________.

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A random variable X has the following probability distribution:

X=xi -2 -1 0 1 2
PX=xi 16 k 14 k 16

The variance of this random variable is

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The mean and standard deviation of random variable X are 10 and 5 respectively, then EX-1552= _________.
MEDIUM

Let X be a random variable with distribution.

x -2 -1 3 4 6
P(X=x) 15 a 13 15 b

If the mean of X is 2.3 and variance of X is σ2, then 100σ2 is equal to :

HARD
Let X be a random variable such that the probability function of a distribution is given by PX=0=12,PX=j=13jj=1,2,3,,. Then the mean of the distribution and P(X is positive and even) respectively, are:
HARD
If 'X' has a binomial distribution with parameters n=6, p and P(X=2)=12, P(X=3)=5, then p=
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A boy tosses fair coin 3 times. If he gets ₹ 2x for x heads then his expected gain equals to ₹........
HARD
In a game, a man wins Rs. 100 if he gets 5 or 6 on a throw of a fair die and loses Rs. 50 for getting any other number on the die. If he decides to throw the die either till he gets a five or a six or to a maximum of three throws, then his expected gain/loss (in rupees) is :