Write the hybridisation and number of unpaired electrons in the complex [ CoF 6 ] 3 - . (Atomic No. of Co = 27 ).

The oxidation number of the given complex ion, CoF 6 3 - is x + 6 × - 1 = - 3 ⇒ x = - 3 + 6 ⇒ x = + 3 . The electronic configuration of the central metal ion is 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 3 d 6 . The fluoride ligand is the weak ligand so, the coordination compound is the outer-orbital complex. Therefore, the hybridization of the compound is sp 3 d 2 . The number of unpaired electron is 4 .

What type of isomerism is exhibited by the complex [ Co ( NH 3 ) 5 Cl ] SO 4 ?

Two or more compounds that have the same chemical formula but, a different arrangement of atoms are known as isomers. In these complexes, there is ionisation isomerism, because both the isomers are identical except for a ligand has exchanged places with an anion that was originally outside the coordination complex, the central metal and other ligands are identical. The isomers are [ Co ( NH 3 ) 5 Cl ] SO 4 and [ Co ( NH 3 ) 5 SO 4 ] Cl .

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Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter -1 - Coordination Compounds>Exercise>Q 32

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The correct formula for diammine silver $(I)$ chloride.

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