The diagram shows a proton as it moves between two charged parallel plates. The charge on the proton is $+1.6\times {10}^{-19}C$

In which direction does the force on the proton act when it is at position $B$ is ?

This diagram shows a proton as it moves between two charged parallel plates. The charge on the proton is $+1.6\times {10}^{-19}C$

What will be the magnitude of the force on the proton when it is at position $C$ ?

The force on the proton when it is at position $B$ is $6.4\times {10}^{-14}\mathrm{N}$.

This diagram shows a proton as it moves between two charged parallel plates. The charge on the proton is $+1.6\times {10}^{-19}C$

 Calculate the electric field strength between the plates.

The force on the proton when it is at position $B$ is $6.4\times {10}^{-14}\mathrm{N}$.

This diagram shows a proton as it moves between two charged parallel plates. The charge on the proton is $+1.6\times {10}^{-19}C$

Calculate the potential difference between the plates.

The force on the proton when it is at position $B$ is $6.4\times {10}^{-14}\mathrm{N}$.

 Define what is meant by the electric field strength at a point.In a particle accelerator, a proton, initially at rest, is accelerated between two metal plates, as shown.

Calculate the force on the proton due to the electric field in the given figure.

Calculate the work done on the proton by the electric field when it moves from plate A to plate B.

State the energy gained by the proton.

Assuming that all the energy is converted to kinetic energy of the proton, calculate the speed of the proton when it reaches plate.

(Charge on a proton $=+1.6\times {10}^{-19}\mathrm{C};$ mass of a proton $=1.7\times {10}^{-27} \mathrm{kg}$.)