Solve: 9 y 7 - 6 y = 15 .

We are given to solve: 9 y 7 - 6 y = 15 ⇒ 9 y = 15 7 - 6 y [By cross multiplication] ⇒ 9 y = 105 - 90 y ⇒ 9 y + 90 y = 105 [By transposing] ⇒ 99 y = 105 ⇒ y = 105 99 ⇒ y = 3 × 35 3 × 33 ⇒ y = 35 33 Hence, the solution is y = 35 33 .

Solve: 2 p - 4 3 p + 2 = - 2 3 .

We are given to solve: 2 p - 4 3 p + 2 = - 2 3 ⇒ 3 2 p - 4 = - 2 3 p + 2 [By cross multiplication] ⇒ 6 p - 12 = - 6 p - 4 ⇒ 6 p + 6 p = 12 - 4 [By transposing] ⇒ 12 p = 8 ⇒ p = 8 12 ⇒ p = 2 3 Hence, the solution is p = 2 3 .

Solve: 2 a - 3 4 9 a + 4 7 = 1 4 .

We are given to solve: 2 a - 3 4 9 a + 4 7 = 1 4 ⇒ 4 2 a - 3 4 = 9 a + 4 7 [By cross multiplication] ⇒ 8 a - 3 = 9 a + 4 7 ⇒ 9 a - 8 a = - 3 - 4 7 [By transposing] ⇒ a = - 21 - 4 7 ⇒ a = - 25 7 Hence, the solution is a = - 25 7 .

E M B I B E

'I Did It' Mathematics>Chapter 7 - Linear Equations in one Variable>Exercise 7.2>Q 9

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The digits of a two-digit number differ by $3$ . If the digits are interchanged, and the resulting number is added to the original number, we get $143$ . What can the original number be?

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Important Questions on Linear Equations in one Variable

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8th CBSE

IMPORTANT

'I Did It' Mathematics>Chapter 7 - Linear Equations in one Variable>Exercise 7.2>Q 10

Shoaib is twice as old as Shehzad. Five years ago his age was three times Shehzad's age. Find their present age.

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8th CBSE

IMPORTANT

'I Did It' Mathematics>Chapter 7 - Linear Equations in one Variable>Exercise 7.2>Q 11

Dinakar's mother's present age is six times Dinakar's present age. Dinakar's age five years from now will be one third of his mother's present age. What is their present age?

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8th CBSE

IMPORTANT

'I Did It' Mathematics>Chapter 7 - Linear Equations in one Variable>Exercise 7.2>Q 12

There is a narrow rectangular plot, reserved for a school, in Malgudi village. The length and breadth of the plot are in the ratio