The dimensional formula of energy is $\left[{\mathrm{M}}^{-1}{\mathrm{L}}^2{\mathrm{T}}^{-2}\right]$.

Ratio of potential energies of body A and body B will be

Match Column I with Column II and select the correct answer from the given codes.

Consider the decay of a free neutron at rest: $n\to p+e^{-}$.
Show that the two-body decay of this type must necessarily give an electron of fixed energy and, therefore, cannot account for the observed continuous energy distribution in the $\mathrm{\beta }$-decay of a neutron or a nucleus (Fig. $6.19$).

Note: The simple result of this exercise was one among the several arguments advanced by W.Pauli to predict the existence of a third particle in the decay products of $\beta$-decay. This particle is known as neutrino. We now know that it is a particle of intrinsic spin 1⁄2 (like $e^{-}$, $p$ or $n$), but is neutral, and either massless or having an extremely small mass (compared to the mass of electron) and which interacts very weakly with matter. The correct decay process of neutron is: $n\to p+e^{-}+\nu$.