Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 11

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Earn 100

The distance between an octahedral and tetrahedral void in FCC lattice would be: $(a = edge length of the unit cell)$

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Important Questions on Solid State

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 12

CdO

has

NaCl

type structure with density

8.27 g / cc

. If the ionic radius of

O^{2 -}

is

1.24 Å

, determine the ionic radius of

{Cd}^{2 +} :

(Molar mass of

CdO = 128 {gmol}^{- 1}

)

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 13

Caesium chloride crystal's interionic distance will be:

(a = edge length)

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 14

In a

BCC

lattice, what fraction of edge is not covered by atoms?

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 15

An atomic solid

A

crystallizes in a body-centred cubic lattice and the surface of the atoms at the adjacent corner are separated by

60.3 pm

. If the atomic weight of

A

is

48

, the density of the solid, is nearly

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 16

For the structure given below, the site marked as $S$ is a:

Question Image

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 17

An element crystallizes in a '

BCC

' lattice. Nearest neighbours and next-nearest neighbours of the element are, respectively:

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 18

The radius of divalent cation $M^{2 +}$ and of divalent anion $X^{2 -}$ is $94 pm$ and $146 pm$ respectively. Thus, $MX$ has:

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Practice Book for MHT-CET Chemistry (Physical Chemistry 2)>Chapter 1 - Solid State>TOPICWISE QUESTIONS>Q 19

{NH}_{4} Cl

crystallizes in a

BCC

type lattice with the edge length of unit cell equal to

387 pm .

If the radius of the

{Cl}^{-}

ion is

181 pm

, then calculate the radius of

{NH}_{4}^{+}

.