The distance between plates of a parallel plate capacitor is $5d$. The positively charged plate is at $x=0$ and the negatively charged plate is at $x=5d$. Two slabs-one of conductor and the other of a dielectric, both of the same thickness $d$ are inserted between the plates as shown in the figure. Potential $\left(V\right)$ versus distance $x$ graph will be

A $400 \mathrm{\mu F}$ condenser is charged at a steady rate of $100 \mathrm{\mu C}$ per second. Calculate the time required to establish a potential difference of $100 \mathrm{volts}$ between its plates.

For the circuit shown in the figure, find

Final energy stored in the capacitor after the switch is closed.

To increase the charge on the plate of a capacitor implies to :-

The net charge on a capacitor is :-

The earth has volume $ V$ and Surface Area $A$ then capacitance would be 

Which of the following is called electrical energy tank ?