The distance between two slits in a double-slit experiment is $1 \mathrm{mm}$. The distance between the slits and the screen is $1 \mathrm{m}$. If the distance of ${10}^{\mathrm{th}}$ fringe from the central fringe is $5 \mathrm{mm}$, then the wavelength of light is

The monochromatic green light of wavelength $5\times {10}^{-7} \mathrm{m}$ illuminates a pair of slits $1 \mathrm{mm}$ apart. The separation of bright lines on the interference pattern formed on a screen $2 \mathrm{m}$ away is

The figure shows a double-slit experiment $P$ and $Q$ is the slits. The path length $PX$ and $QX$ are $n\lambda$ and $\left(n+2\right)\lambda$, respectively, where $n$ is a whole number and $\lambda$ is the wavelength. Taking the centre fringe as zero, what is formed at $X$

In Young's double slit experiment, $62$ fringes are seen in visible region for sodium light of wavelength $5893 \mathrm{\AA }$. If violet light of wavelength $4358 \mathrm{\AA }$ is used in place of sodium light, then number of fringes seen will be

If in Young's double-slit experiment, the slit distance is $3 \mathrm{cm}$, the separation between slits and screen is $70 \mathrm{cm}$ and wavelength of light is $1000 \stackrel{\circ }{\mathrm{A}}$, then fringe width will be