The distinguishing property of transverse and longitudinal waves is that

The transverse waves can propagate through

A travelling wave passes through a point of observation. At this point, the time interval between successive crests is $0.2 \mathrm{s}$, then,

When a wave travels in a medium, displacement of a particle is given by, $y(x,t)=0.03\sin \pi (2t-0.01x)$, where $y$ and $x$ are in metres and $t$ in seconds. The phase difference at a given instant of time between two particles $25 \mathrm{m}$ apart in the medium is

The equations of displacement of two waves are given as $y_1=10\sin \left(3\pi t+\frac{\pi }{3}\right)$, 
$y_2=5(\sin 3\pi t+\sqrt{3}\cos 3\pi t).$ Then what is the ratio of their amplitudes? 

The equation of a transverse wave is given by, $\Psi ={10}^{-2}\sin \pi [30t-x\sqrt{3}-y]$ where $x\text{,} y$ and $\Psi$ are in $\mathrm{metre}$ and $t$ in $\sec$. If phase difference between two points, $A (2\sqrt{3} \mathrm{m}\text{,} 2 \mathrm{m})$ and $B (3\sqrt{3} \mathrm{m}\text{,} 3 \mathrm{m})$ is $n\pi$, find the value of $n$.