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The electric potential V as a function of distance x (in metre) is given by V=5x2+10x9 volt. The value of the electric field at x=1 m would be

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Important Questions on Electrostatics

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A uniform electric field having a magnitude E0, directed along positive x-axis exists. If the electric potential V is zero at x=0, then its value at x=+x will be
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A uniform electric field pointing in positive X direction exists in a region. Let A be the origin, B be the point on the X-axis at x=+1 cm and C be the point on the Y-axis at y=+1 cm. Then the potentials at A, B and C satisfy-
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A 5 coulomb charge experiences a constant force of 2000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between these two points is:
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An equipotential surface and an electric line of force:
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If an electric dipole is kept in a non-uniform electric field, then it will experience:
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The force on a charge situated on the axis of a dipole is F. If the charge is shifted to double the distance, the acting force will be -
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A dipole of dipole moment P, is placed in an electric field E and is in stable equilibrium. The torque required to rotate the dipole from this position by angle θ will be -
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The electric potential at a point due to an electric dipole will be -