Below each item in the first column write the numbers of the appropriate items from the other two columns to match. ( R e q = equivalent resistance of the combination, I e a c h current through each resistor, V e a c h = potential difference across each resistor, and so on) Column I Column II Column III A A potential difference V is applied across a parallel combination of 4 equal resistors R. i . R e q = 4 R 1 . I c i r c u i t = 4 V / R i i . R e q = R 2 . I c i r c u i t = V / R B A current I passes through a combination of 2 equal resistors R connected in series. i i i . R e q = R / 4 3 . I c i r c u i t = 2 V / R i v . R e q = 2 R 4 . V R e g = 2 i R C A potential difference 2V is applied across a parallel combination of 2 equal resistors of resistance 2R. v . R e q = 1 / 2 R 5 . V e a c h = V V i . R e q = 1 / 4 R 6 . V e a c h = I R D A potential difference 2V is applied across a series combination of 2 equal resistors of resistance 2 R. V i i . R e q = R / 2 7 . I e a c h = V / R

A matched with iii, 1, 5, 7. Explanation: A potential difference V is applied across a parallel combination of four equal resistors R . Let four resistance be R 1 , R 2 , R 3 , R 4 . Then, R 1 = R 2 = R 3 = R 4 = R (given) Potential difference V = V Let current in each branch be i each and equivalent resistance be R eq . Then, 1 R e q = 1 R 1 + 1 R 2 + 1 R 3 + 1 R 4 1 R eq = 1 R + 1 R + 1 R + 1 R 1 R eq = 4 R R eq = R 4 As, these resistances are connected in parallel, so the potential difference remains same. Current in each branch will be, I e a c h = V R and circuit current will be the sum of current in each branch, I circuit = I 1 + I 2 + I 3 + I 4 I 1 = I 2 = I 3 = I 4 = I each I circuit = 4 I each I circuit = 4 V R B matched with iv, 4, 6. Explanation: A current I is applied across a series combination of two equal resistors R . Let two resistance be R 1 , R 2 . Then, R 1 = R 2 = R (given) current I Let voltage in each branch be V each and equivalent resistance be R eq . Then, R e q = R 1 + R 2 R eq = R + R R eq = 2 R As, these resistances are connected in series, so the current remains same. Voltage in each branch will be, V each = I R and circuit voltage will be the sum of voltage in each branch, V circuit = V 1 + V 2 V 1 = V 2 = V each V circuit = 2 V each V circuit = 2 I R C matched with ii, 3, 7. Explanation: A potential difference 2 V is applied across a parallel combination of two equal resistors 2 R . Let two resistance be R 1 , R 2 . Then, R 1 = R 2 = 2 R (given) Potential difference V = 2 V Let current in each branch be I each and equivalent resistance be R eq . Then, 1 R e q = 1 R 1 + 1 R 2 1 R eq = 1 2 R + 1 2 R 1 R eq = 2 2 R R eq = R As, these resistances are connected in parallel, so the potential difference remains same. Current in each branch will be, I e a c h = V R and circuit current will be the sum of current in each branch, I circuit = I 1 + I 2 I 1 = I 2 = I each I circuit = 2 I each I circuit = 2 V R D matched with i, 2, 5. Explanation: A potential difference 2 V is applied across a series combination of two equal resistors 2 R . Let two resistance be R 1 , R 2 . Then, R 1 = R 2 = 2 R (given) current I Let voltage in each branch be V each and equivalent resistance be R eq . Then, R e q = R 1 + R 2 R eq = 2 R + 2 R R eq = 4 R As, these resistances are connected in series, so the current remains same. voltage in circuit will be, V circuit = 2 V Current in the circuit, I = V circuit R eq I = 2 V 4 R I = V 2 R Voltage in each branch will be, V e a c h = I R e a c h V e a c h = V 2 R × 2 R V e a c h = V Column I Column II Column III A A potential difference V is applied across a parallel combination of 4 equal resistors R. R e q = R / 4 I c i r c u i t = 4 v R V e a c h = V I each = V R B A current i passes through a combination of 2 equal resistors R connected in series. R e q = 2 R V R e q = 2 I R V e q c h = I R C A potential difference 2V is applied across a parallel combination of 2 equal resistors of resistance 2R. R e q = R I c i r c u i t = 2 v R I e a c h = V R D A potential difference 2V is applied across a series combination of 2 equal resistors of resistance 2 R. R e q = 4 R I c i r c u i t = v R V e a c h = V

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The electron volt is a unit of energy.

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Important Questions on Question Bank 1

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Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q II

The magnetic field outside a current-carrying solenoid is parallel to the axis of the solenoid.

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10th CBSE

IMPORTANT

Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q II

The poles of an electromagnet get switched if the direction of the current is reversed.

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10th CBSE

IMPORTANT

Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q II

The resistance of a wire is directly proportional to its area of cross section.

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IMPORTANT

Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q II

The heat produced in a current-carrying wire is proportional to the square of the current.

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10th CBSE

IMPORTANT

Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q II

One unit of electrical energy means

1000 watt hours

of electrical energy.

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10th CBSE

IMPORTANT

Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q III

Below each item in the first column write the numbers of the appropriate items from the other two columns to match. (

R_{e q =}

equivalent resistance of the combination,

I_{e a c h}

current through each resistor,

V_{e a c h}

= potential difference across each resistor, and so on)

Column I		Column II	Column III
A	A potential difference V is applied across a parallel combination of 4 equal resistors R.	$i . R_{e q} = 4 R$	$1 . I_{c i r c u i t = 4 V / R}$
		$i i . R_{e q} = R$	$2 . I_{c i r c u i t} = V / R$
B	A current I passes through a combination of 2 equal resistors R connected in series.	$i i i . R_{e q} = R / 4$	$3 . I_{c i r c u i t} = 2 V / R$
		$i v . R_{e q} = 2 R$	$4 . V_{R_{e g}} = 2 i R$
C	A potential difference 2V is applied across a parallel combination of 2 equal resistors of resistance 2R.	$v . R_{e q} = 1 / 2 R$	$5 . V_{e a c h} = V$
		$V i . R_{e q} = 1 / 4 R$	$6 .$ $V_{e a c h} = I R$
D	A potential difference 2V is applied across a series combination of 2 equal resistors of resistance 2 R.	$V i i . R_{e q} = R / 2$	$7 . I_{e a c h} = V / R$
		$V i i . R_{e q} = R / 2$	$7 . I_{e a c h} = V / R$

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10th CBSE

IMPORTANT

Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q 1

When one volt is applied across an element, a current of one ampere flows through the element. What is the resistance of the element?

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10th CBSE

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Foundation Science Physics for Class 10>Chapter 7 - Question Bank 1>Question Bank>Q 2

The figure below shows a magnetic compass placed just below a wire. If the compass is placed just above the wire and a current is passed as before, towards which direction will the needle get deflected?

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The electron volt is a unit of energy.

Important Questions on Question Bank 1

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