Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 19

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Earn 100

The energy required to pull out an electron from the first orbit of hydrogen atom to infinity is $100 units$ . The amount of energy needed to pull out the electron from the second orbit to infinity is

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Important Questions on Structure of Atom

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 20

If the first excitation potential of a hypothetical

H -

like atom is

10.2 x V,

then the value of the second excitation energy is about

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 21

The kinetic energy of the electron present in the ground state of

{Li}^{2 +}

ion is represented by

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 22

If the energy of an electron in a hydrogen atom is given by the expression,

- 1312 / n^{2} {kJmol}^{- 1},

then the energy required to excite the electron from the ground state to the second orbit is

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 23

The frequency of radiation emitted when the electron falls from $n = 2$ to $n = 1$ in a hydrogen atom will be

$(h = 6.625 \times 10^{- 34} Js)$

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 24

The kinetic energy of an electron in the second orbit of a hydrogen atom is

( $a_{0}$ is Bohr radius of the first orbit)

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 25

If the series limit to the wavelength of the Lyman series of the hydrogen atom is

912 Å

, then the series limit to the wavelength for the Balmer series of the hydrogen atom is

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 26

The difference between the wave number of first line of Balmer series and last line of paschen series for

{Li}^{2 +}

ion is

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Alpha Question Bank for Medical: Chemistry>Chapter 2 - Structure of Atom>Exercise 2>Q 27

If the shortest wavelength of the Lyman series of

H

atom is

x

, then the wavelength of the first line of the Balmer series of

H

atom will be: