MEDIUM
JEE Main/Advance
IMPORTANT
Earn 100

The equation of a standing wave produced on a string fixed at both ends at x=0 and x=L respectively is y=0.8 cmsin0.314 cm-1x cos600π s-1t. Choose the correct statement(s)

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Important Questions on Waves

HARD
JEE Main/Advance
IMPORTANT
A string of length 50 cm and mass 2.5 g is fixed at both ends with a tension of 52 N. A closed organ pipe has length 85 cm. The string vibrates in its second overtone and the air column in the pipe in its first overtone. Neglect the end correction in the pipe and the speed of sound in air is 340 m s-1. Then
HARD
JEE Main/Advance
IMPORTANT
A standing wave given by the equation, S=S0 sinkx.coswt is maintained in a homogeneous rod with cross-sectional area A and density d, where S represents displacement of a particle from its mean position. Then select the correct statement(s)
HARD
JEE Main/Advance
IMPORTANT
A wave disturbance in a medium is described by yx, t=0.04cos50πt+π2cos10πx, where x and y are in meters and'f' is in seconds.
(i) Displacement node occurs at x=0.15 m
(ii) At t=150 s, particle at x=0.20 m will be moving with speed 2π m s-1
(iii) At t=1100 s, particle at x=115 m will beat a displacement of 0.02 m from it's own mean position
(N) At t=3100 s, particle at x=115 m will beat a displacement of 0.02 m from it's own mean position
HARD
JEE Main/Advance
IMPORTANT
A taut string (fixed at both ends) vibrates in its mth overtone. The minimum distance between two points which is vibrating with maximum possible amplitude A and half of the maximum possible amplitude A2 respectively is'd'. Then length'L' of the string is
EASY
JEE Main/Advance
IMPORTANT

Three waves are propagating in same direction and pass through a point simultaneously. The variation of electric field with time is as

E1=E0cosωt, E2=2E0sinωt and
E3=5E0cosωt+53°; and intensity due to
first wave at that point is I0. Then

MEDIUM
JEE Main/Advance
IMPORTANT
A uniform string of linear mass density 0.5 kg m-1 is stretched to a tension of 800 N. If mean power (in W) required to maintain a travelling wave of amplitude of 5 mm and wavelength 0.1 m is k×2π2, then find integral value of k.
MEDIUM
JEE Main/Advance
IMPORTANT
The ratio of intensities between two coherent sound source is 9 : 4. If difference of loudness in dB between maximum and minimum intensities when they interfere in space is 10 log k, then find k.