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The equation of an SHM with amplitude A and angular frequency ω in which all the distances are measured from one extreme position and time is taken to be zero at the other extreme position is

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Important Questions on Oscillations

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A body oscillates with SHM according to the equation x=(5.0 m)cos2πrads-1t+π/4 At t=1.5 s, its acceleration is
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The period of a particle executing SHM is 8 s. At t=0, it is at the mean position. The ratio of the distances covered by the particle in the 1st second to the 2nd second is
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Figure shows the position-time graph of an object in SHM. The correct equation representing this motion is
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A particle executes SHM and its position varies with time as x=Asinωt. Its average speed during its motion from mean position to mid-point of mean and extreme position is
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A particle is executing SHM and its velocity v is related to its position (x) as v2+ax2=b, where a and b are positive constants. The frequency of oscillation of particle is
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A particle executes SHM according to equation x=10( cm)cos2πt+π2, where t is in second. The magnitude of the velocity of the particle at t=16 s will be
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Two particles executing SHM of same amplitude of 20 cm with same period along the same line about same equilibrium position. The maximum distance between the two is 20 cm. Their phase difference in radian is equal to
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A particle executes SHM along a straight line. The amplitude of oscillation is 2 cm. When displacement of particle from the mean position is 1 cm, the magnitude of its acceleration is equal to magnitude of its velocity. The time period (in seconds) of oscillation is