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The equation z2=z- has

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Important Questions on Complex Numbers

MEDIUM
If Rez-12z+i=1, where z=x+iy, then the point x,y lies on a
HARD
A value of θ for which 2+3isinθ1-2isinθ is purely imaginary, is
HARD
Let zC with Im(z)=10 and it satisfies 2z-n2z+n=2i-1 for some natural number n. Then
MEDIUM
If 1+i1-im2=1+ii-1n3=1,  m, nN then the greatest common divisor of the least values of m and n is
MEDIUM
For all complex numbers z of the form 1+iα, αR, if z2=x+iy, then 
HARD
The imaginary part of 3+2-5412-3-2-5412, can be
MEDIUM
Let z=1+ai, be a complex number, a>0, such that z3 is a real number. Then, the sum 1+z+z2+.+z11 is equal to :
MEDIUM
If A=z=x+iy/real part of z¯-1z-i=2 then the locus of the point Px,y in the Cartesian plane is
HARD
Let wIm w≠0 be a complex number. Then, the set of all complex numbers z satisfying the equation w-w¯z=k1-z, for some real number k, is
MEDIUM
If 32+cosθ+isinθ=a+ib, then [a-22+b2] is equal to
EASY
Let z=x+iy be a non-zero complex number such that z2=i|z|2, where i=-1, then z lies on the
EASY
The imaginary part of conjugate of 1+i1-i5 is
MEDIUM
If z=x+iy, z13=a-ib, then xa-yb=ka2-b2 where k is equal to
EASY
Simplified form of 10i1+2i is equal to
MEDIUM
Let zC and i=-1, if a, b, c 0,1 be such that a2+b2+c2=1 and b+ic=1+az, then 1+iz1-iz=
EASY
The conjugate of a complex number is 11-i. Then the complex number is
HARD
Let z1 and z2 be the roots of the equation z2+pz+q=0 where p, q are real. The points represented by z1, z2 and the origin form an equilateral triangle, if
EASY
The area of the triangle in the complex plane formed by z, iz and z+iz is