Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 5

EASY

JEE Main

IMPORTANT

Earn 100

The equivalent weight of iodine in $I_{2} + 2 S_{2} O_{3}^{2 -} \to 2 I^{-} + S_{4} O_{6}^{2 -}$ , is equal to its

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Important Questions on Volumetric Calculation

EASY

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 6

The equivalent weight of

K_{2} {Cr}_{2} O_{7}

as an oxidising agent in acid medium is

EASY

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 7

In alkaline condition, ${KMnO}_{4}$ reacts as follows:

$2 {KMnO}_{4} + 2 KOH \to 2 K_{2} {MnO}_{4} + H_{2} O + O$ ,

The equivalent weight for ${KMnO}_{4}$ is

EASY

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IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 8

0.126 g

of an acid requires

20 mL

of

0.1 N NaOH

for complete neutralisation. The equivalent weight of the acid is:

MEDIUM

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 9

H_{3} {PO}_{4}

is a tribasic acid and one of its salt is

{NaH}_{2} {PO}_{4}

. What volume of

1 M

NaOH

solution should be added to

12 g

of

{NaH}_{2} {PO}_{4}

to convert it into

{Na}_{3} {PO}_{4}

?

EASY

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 10

2 g

of a base whose equivalent weight is

40

, reacts with

3 g

of an acid. The equivalent weight of the acid will be

EASY

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 11

In a reaction,

4

moles of electrons are transferred to one mole of

{HNO}_{3}

when acted as an oxidant. The possible reduction product is

EASY

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 12

Normality of

1 % H_{2} {SO}_{4}

solution is nearly

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JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 7 - Volumetric Calculation>Objective Problems>Q 13

What volume of

0.1 N {HNO}_{3}

solution can be prepared from

6.3 g

of

{HNO}_{3}

?