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The escape velocity from the surface of earth is ve. The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be

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Important Questions on Gravitation

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The escape velocities of the two planets, of densities ρ1 and ρ2 and having same radius, are v1 and v2 respectively. Then
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The ratio of escape velocity at earth ve to the escape velocity at a planet vp whose radius and mean density are twice as that of the earth is
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A satellite is revolving in a circular orbit at a height h from the earth's surface (radius of earth R;h<<R). The minimum increase in its orbital velocity required, so that the satellite could escape from the earth's gravitational field, is close to (Neglect the effect of atmosphere).
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A satellite is moving with a constant speed v in a circular orbit about the earth. An object of mass m is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of its ejection, the kinetic energy of the object is
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Given mass of the moon is 181 of the mass of the earth and corresponding radius is 14 of the radius of earth. If escape velocity on the earth's surface is 11.2 km s-1, the value of same on the surface of the moon is
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Two satellites A and B are rotating in a same orbit. The ratio of their escape velocities, if both the radius and mass of A is twice that of B is
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The escape velocity of a body on an imaginary planet which is thrice the radius of the earth and double the mass of the earth is (ve is the escape velocity of earth)
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A black hole is an object whose gravitational field is so strong that even light cannot escape from it. To what approximate radius would earth (mass =6×1024 kg) have to be compressed to be a black hole?