The external and internal radius of the mouth of a metal hemispherical bowl is $5 \mathrm{cm} \mathrm{and} 4 \mathrm{cm}$. What will be the cost (in $₹$) of painting the whole surface of the bowl at the rate of $10$ paisa per $\mathrm{sq}.\mathrm{cm}$. [Take $\mathrm{\pi }=\frac{22}{7}$]