The figure shows the variation of electrostatic potential $V$ in volt with the distance of position of point along $x$ - axis from origin due to continuous volume charge distribution. In the region $x=-1 \mathrm{m}$ to $x=+1 \mathrm{m}$, the graph is parabolic $\left(V=15-5x^2\right)$ and rest portion of graph is straight line. Choose the correct option(s) $\left({\epsilon }_0\Rightarrow \right.$permittivity of free space $\left.=8.85\times {10}^{-12} {\mathrm{N}}^{-1} {\mathrm{m}}^{-2} {\mathrm{C}}^2\right)$. The direction of $\overrightarrow{E}$ along positive $x$-axis is considered as positive.

 

Figure shows three points $A,B$ and $C$ in a region of uniform electric Field $\overrightarrow{E}$. The line $AB$ is perpendicular and $BC$ is parallel to the field lines. Then which of the following hold good? ($V_A,V_B$ and $V_C$ represent the electric potential at points $A, B$ and $C$ respectively )

The figure gives the electric potential $V$ as a function of distance through four regions on $x$-axis. Which of the following is true for the magnitude of the electric field $E$ in these regions?

As shown in the figure below, a point charge $q$ moves from point $P$ to a point $S$ traversing a path $PQRS$ in a uniform $\overrightarrow{E}.$ The electric field is directed along a direction parallel to $x$-axis. The coordinates of, $P,Q,R$ and $S$ are $\left(a,b,0\right)\left(2a,0,0\right)\left(a,-b,0\right)$ and $\left(0,0,0\right)$ respectively. What is the work done by the field in the process?

An imaginary equilateral triangle $ABC$ of side length $2 \mathrm{m}$ is placed in a uniform electric field $\overrightarrow{\mathrm{E}}=10 \mathrm{N} {\mathrm{C}}^{-1}$ as shown. Then. $V_A-V_B=$

An electron is placed on $X$-axis where the electric potential depends on $x$ as shown in figures (the potential does not depend on $y$ and $z$ ). What is the electric force on the electron?