The figure shows three points $A$, $B$ and $C$ in a region of a uniform electric field $\overrightarrow{E}$. The line $AB$ is perpendicular and $BC$ is parallel to the field lines. Then which of the following holds good?



(Where ${\mathrm{V}}_{\mathrm{A}},{\mathrm{V}}_{\mathrm{B}}$ and ${\mathrm{V}}_{\mathrm{c}}$ represent the electric potential at the points $\mathrm{A}$, $\mathrm{B}$ and $\mathrm{C}$ respectively)

Figure shows three arrangements of electric field lines. In each arrangement, a proton is released from rest at point A and then accelerated through point B by the electric field. Points A and B have equal separations in the three arrangements. If $p_1,p_2$ and $p_3$ are linear momentum of the proton at point B in the three arrangement respectively, then

What is the direction of electric field with respect to an equipotential surface?

A small point mass carrying some positive charge on it, is released from the edge of a table. There is a uniform electric field in this region in the horizontal direction. Which of the following options then correctly describe the trajectory of the mass ? (Curves are drawn schematically and are not to scale)

Draw equipotential surface due to an isolated point charge$\left(-q\right)$ and depict the electric field lines.

Define:

$\left(\mathrm{b}\right)$ Equipotential surface.

The electric field lines on the left have twice the separation on those on the right as shown in figure. If the magnitude of the field at $A$ is $40 {\mathrm{Vm}}^{-1}$, what is  the force on $20 \mu \mathrm{C}$ charge kept at