The following curve is obtained when molar conductivity,${\mathrm{\Lambda }}_{\mathrm{m}}$ is plotted against the square root of concentration, ${\mathrm{C}}^{1/2}$ along $\mathrm{B}$ and $\mathrm{A}$-axis respectively for the two electrolytes $\mathrm{A}$ and $\mathrm{B}$. Account for the increase in ${\mathrm{\Lambda }}_{\mathrm{m}}$ for the electrolytes $\mathrm{A}$ and $\mathrm{B}$ with dilution.

 

The following curve is obtained when molar conductivity, ${\mathrm{\Lambda }}_{\mathrm{m} }$ is plotted against the square root of concentration,${\mathrm{C}}^{1/2}$ along $\mathrm{B}$and $\mathrm{A}$-axis respectively for the two electrolytes $\mathrm{A}$ and $\mathrm{B}$. Determine ${{\mathrm{\Lambda }}^{\infty }}_{\mathrm{m}}$ for these electrolytes.

How many moles of $\mathrm{Hg}$ will be produced by electrolysing $1.0 \mathrm{M} \mathrm{Hg}({\mathrm{NO}}_3{)}_2$ solution with a current of $2.00 \mathrm{A}$ for $3$ hours?

$\left[\mathrm{Hg}\right({\mathrm{NO}}_3{)}_2= 200.6 \mathrm{g}/\mathrm{mol}]$