The following figure shows a logic gate circuit with inputs $\text{'}A\text{'}$ and $\text{'}B\text{'}$ and output $\text{'}Y\text{'}.$ If the voltage wave forms of $A, B$ and $Y$ are as given, then the logic gate is

Identify the logic operation carried out.

The truth table given below corresponds to logic gate.

$\begin{array}{|ccc|}\hline \mathbf{A}& \mathbf{B}& \mathbf{X}\\ 0& 0& 0\\ 0& 1& 1\\ 1& 0& 1\\ 1& 1& 1\\ \hline\end{array}$

The truth table for the following logic circuit is :

In the given circuit, the input voltages at $\mathrm{P}$ and $\mathrm{Q}$ could be either $0 \mathrm{V}$ or $10 \mathrm{V}$. Use the fact that a diode under forward bias is a short circuit, and under reverse bias is an open circuit. The truth table of the circuit will be that of

Refer the given circuit diagram. Using the given inputs, write the truth table to get the output Y :

The output of the given combination gates represents:

For the following logic circuit, 

$Y=0$ for $A=1, B=1, C=1$
$Y=0$ for $A=0, B=0, C=0$
$Y=1$ for $A=1, B=0, C=0$

The logic gate in the question-marked box will be,

Write value of output $\mathrm{Y}$ in diagram.

The truth table for the given logic circuit is:

In the circuit the output $y$ becomes zero for the inputs

Find the truth table for the function $Y$ of $A$ and $B$ represented in the following figure.

The truth table for the given logic circuit is

Identify the correct output signal $Y$ in the given combination of gates (as shown $n$) for the given inputs $A and B$