The general formula of a homologous series of carbon compounds is ${\mathrm{C}}_{\mathrm{n}}{\mathrm{H}}_{2\mathrm{n}}$. Write the molecular formula of the second and fourth members of the series.

The molecular formula of one homologue of ${\mathrm{C}}_2{\mathrm{H}}_2$ can be ${\mathrm{C}}_{\mathrm{x}}{\mathrm{H}}_{\mathrm{y}}$.

The value of x and y in the formula can be-

A. x = 3, y = 4

B. x = 4, y = 6

C. x = 5, y = 8

"Enter your correct answer as A, B or C."