The largest four digit number which is a perfect cube is

$\sqrt[3]{\frac{-125}{81}}=?$

If $\frac{\sqrt[3]{0.512}}{x}=\sqrt[3]{1000000}$, then the value of $x$ is

By what least number should $1372$ be multiplied so that the product is a perfect cube. Also find the cube root of the product so obtained.

If the cube root of $175616$ is $56$, then find the value of $\sqrt[3]{175.616}+\sqrt[3]{0.175616}+\sqrt[3]{0.000175616}$

Find $\sqrt[3]{\frac{3^6\times 4^3\times 2^9}{8^6\times 2^6}}$