The latus rectum of the parabola $y^2=-8x\text{ is }2$.

The eccentricity of the parabola $(y-1{)}^2=4(x+3)\text{ is }\frac{1}{3}$.

The line $y=3$ is a tangent to the parabola $(x+2{)}^2=6(y-3)$.

The equation $A{x}^2+B{y}^2=1$ represents an ellipse with its axis parallel to $x-$axis if $A > B >0$.

The foci of the ellipse $\frac{x^2}{3}+\frac{y^2}{2}=1$ are the points $(\pm 1,0)$.

The equation of the ellipse with foci at $(0,\pm 4)$ and vertices at $(0,\pm 7)$ is $\frac{x^2}{16}+\frac{y^2}{49}=1$.

The length of the latus rectum of the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1\text{ and }\frac{(x+2{)}^2}{4}+\frac{(y-1{)}^2}{9}=1$ are equal.

The equation of the latus recta of the ellipse $\frac{(x-4{)}^2}{16}+\frac{(y-1{)}^2}{9}\text{ are }x=4\pm \sqrt{7}$.

The line $y=x+2$ is a tangent to the ellipse $\frac{x^2}{2}+\frac{y^2}{1}=1$.