The length of a germanium rod is $0.58 \mathrm{cm}$ and its area of cross-section is $1 {\mathrm{mm}}^2$. If for germanium ${\mathrm{n}}_i=2.5\times {10}^{19} {\mathrm{m}}^{–3}, {\mathrm{\mu }}_h=0.19 {\mathrm{m}}^2 {\left(\mathrm{V} \mathrm{s}\right)}^{-1}, {\mathrm{\mu }}_e=0.39 {\mathrm{m}}^2 {\left(\mathrm{V} \mathrm{s}\right)}^{-1},$ then the resistance of the rod will be -