MEDIUM

JEE Main

IMPORTANT

Earn 100

The length of the perpendicular from the point $(2, - 1, 4)$ on the straight line $\frac{x + 3}{10} = \frac{y - 2}{- 7} = \frac{z}{1}$ is

50% studentsanswered this correctly

Important Questions on Three Dimensional Geometry

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 8th April 2019 Shift 1>Q 81

The equation of a plane containing the line of intersection of the planes

2 x - y - 4 = 0

and

y + 2 z - 4 = 0

and passing through the point

(1,1, 0)

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 8th April 2019 Shift 2>Q 82

The vector equation of the plane through the line of intersection of the planes

x + y + z = 1

and

2 x + 3 y + 4 z = 5

which is perpendicular to the plane

x - y + z = 0

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 8th April 2019 Shift 2>Q 83

If a point

R (4, y, z)

lies on the line segment joining the points

P (2, - 3,4)

and

Q (8,0, 10),

then the distance of

R

from the origin is

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 10th April 2019 Shift 1>Q 84

If the length of the perpendicular from the point

(β, 0, β), (β \neq 0)

to the line,

\frac{x}{1} = \frac{y - 1}{0} = \frac{z + 1}{- 1}

\sqrt{\frac{3}{2}}

, then

β

is equal to

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 10th April 2019 Shift 1>Q 85

Let

A (3, 0, - 1), B (2, 10, 6)

and

C (1, 2, 1)

be the vertices of a triangle and

M

be the mid-point of

A C

. If

G

divides

B M

in the ratio,

2 : 1

, then

c o s (∠ G O A)

(

O

being the origin) is equal to

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 10th April 2019 Shift 2>Q 86

The distance of the point having position vector

- \hat{i} + 2 \hat{j} + 6 \hat{k}

from the straight line passing through the point

(2, 3, - 4)

and parallel to the vector,

6 \hat{i} + 3 \hat{j} - 4 \hat{k}

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 10th April 2019 Shift 2>Q 87

If the plane

2 x - y + 2 z + 3 = 0

has the distances

\frac{1}{3}

and

\frac{2}{3}

units from the planes

4 x - 2 y + 4 z + λ = 0

and

2 x - y + 2 z + μ = 0

, respectively, then the maximum value of

λ + μ

is equal to:

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 20 - Three Dimensional Geometry>JEE Main - 10th April 2019 Shift 2>Q 88

A perpendicular is drawn from a point on the line

\frac{x - 1}{2} = \frac{y + 1}{- 1} = \frac{z}{1}

to the plane

x + y + z = 3

such that the foot of the perpendicular

Q

also lies on the plane

x - y + z = 3

. Then the coordinates of

Q

are

The length of the perpendicular from the point (2,-1, 4) on the straight line x+3 10=y-2-7=z1 is

Important Questions on Three Dimensional Geometry

Learn and Prepare for any exam you want !

The length of the perpendicular from the point $(2, - 1, 4)$ on the straight line $\frac{x + 3}{10} = \frac{y - 2}{- 7} = \frac{z}{1}$ is