The linear equation that converts Fahrenheit $\left(F\right)$ to Celsius $\left({}^{\circ }\mathrm{C}\right)$ is given by the relation:

$C=\frac{5F-160}{9}$

If the temperature is $86°\mathrm{F}$, what is the temperature in Celsius?

The linear equation that converts Fahrenheit $\left(F\right)$ to Celsius $\left({}^{\circ }\mathrm{C}\right)$ is given by the relation:

$C=\frac{5F-160}{9}$

If the temperature is $35°\mathrm{C},$ what is the temperature in Fahrenheit?

The linear equation that converts Fahrenheit $\left(F\right)$ to Celsius $\left({}^{\circ }\mathrm{C}\right)$ is given by the relation:

$C=\frac{5F-160}{9}$

If the temperature is $0°\mathrm{C},$ what is the temperature in Fahrenheit and if the temperature is $0°\mathrm{F}$, what is the temperature in Celsius?

The linear equation that converts Fahrenheit $\left(F\right)$ to Celsius $\left({}^{\circ }\mathrm{C}\right)$ is given by the relation:

$C=\frac{5F-160}{9}$

What is the numerical value of temperature which is same in both the scales?

If the temperature of a liquid can be measured in Kelvin units as $x°\mathrm{K}$ or in Fahrenheit units as $y°\mathrm{F}$, the relation between the two systems of measurement of temperature is given by the linear equation

$y=\frac{9}{5}(x-273)+32$

If the temperature of the liquid in Fahrenheit is $t°\mathrm{F}$ and the temperature of the liquid in Kelvin is $313°\mathrm{K}$, then find the value of $t$.

If the temperature of a liquid can be measured in Kelvin units as $x°\mathrm{K}$ or in Fahrenheit units as $y°\mathrm{F}$, the relation between the two systems of measurement of temperature is given by the linear equation

$y=\frac{9}{5}(x-273)+32$

 If the temperature is $158°\mathrm{F}$ and the temperature in Kelvin is $t°\mathrm{K}$, then find the value of $t$.

The force exerted to pull a cart is directly proportional to the acceleration produced in the body.

Express the statement as a linear equation in two variables and draw the graph of the same by taking the constant mass equal to $6 kg$. Read from the graph, the force required when the acceleration produced in the body is $5\mathrm{m}/{\mathrm{s}}^2$.

The force exerted to pull a cart is directly proportional to the acceleration produced in the body.

Express the statement as a linear equation in two variables and draw the graph of the same by taking the constant mass equal to $6 \mathrm{kg}$. Read from the graph, the force required when the acceleration produced in the body is  $6\mathrm{m}/{\mathrm{s}}^2$.