MEDIUM
JEE Main
IMPORTANT
Earn 100

The magnetic field of a plane electromagnetic wave is given by B=2×10-8sin0.5×103x+1.5×1011tj^ T. The amplitude of the electric field would be

100% studentsanswered this correctly

Important Questions on Electromagnetic Waves

HARD
JEE Main
IMPORTANT
The oscillating magnetic field in a plane electromagnetic wave is given by By=5×10-6sin1000π5x-4×108t T. The amplitude of electric field will be
MEDIUM
JEE Main
IMPORTANT

A beam of light travelling along X-axis is described by the electric field Ey=900sinωt-xc. The ratio of electric force to magnetic force on a charge q moving along Y-axis with a speed of 3×107 m s-1 will be :

[Given speed of light =3×108 m s-1 ]

EASY
JEE Main
IMPORTANT

Identify the correct statements from the following descriptions of various properties of electromagnetic waves.

A. In a plane electromagnetic wave electric field and magnetic field must be perpendicular to each other and direction of propagation of wave should be along electric field or magnetic field.

B. The energy in electromagnetic wave is divided equally between electric and magnetic fields.

C. Both electric field and magnetic field are parallel to each other and perpendicular to the direction of propagation of wave.

D. The electric field, magnetic field and direction of propagation of wave must be perpendicular to each other.

E. The ratio of amplitude of magnetic field to the amplitude of electric field is equal to speed of light.

Choose the most appropriate answer from the options given below:

MEDIUM
JEE Main
IMPORTANT
Sun light falls normally on a surface of area 36 cm2 and exerts an average force of 7.2×10-9 N within a time period of 20 minutes. Considering a case of complete absorption, the energy flux of incident light is
EASY
JEE Main
IMPORTANT

Match List - I with List - II

  List-I   List-II
(a) UV rays (i) Diagnostic tool in medicine
(b) X-rays (ii) Water purification
(c) Microwave (iii) Communication, Radar
(d) Infrared wave (iv) Improving visibility in foggy days

Choose the correct answer from the options given below :

MEDIUM
JEE Main
IMPORTANT
Nearly 10% of the power of a 110 W light bulb is converted to visible radiation. The change in average intensities of visible radiation, at a distance of 1 m from the bulb to a distance of 5 m is a×10-2 W m-2. The value of 'a' will be
MEDIUM
JEE Main
IMPORTANT

If E and K represent electric field and propagation vectors of the EM waves in vacuum, then magnetic field vector is given by:

(ω- angular frequency)

EASY
JEE Main
IMPORTANT

The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by

 Ex=E0sinkz-ωt

By=B0sinkz-ωt

Then the correct relation between E0 and B0 is given by