The magnetic field of an electromagnetic wave is given by: B → = 1.6 × 10 - 6 cos ⁡ 2 × 10 7 z + 6 × 10 15 t 2 i ^ + j ^ W b m 2 The associated electric field will be:

E → = 4.8 × 10 2 c o s 2 × 10 7 z + 6 × 10 15 t - i ^ + 2 j ^ V m

E → = 4.8 × 10 2 c o s 2 × 10 7 z - 6 × 10 15 t - 2 j ^ + i ^ V m

E → = 4.8 × 10 2 c o s 2 × 10 7 z + 6 × 10 15 t i ^ - 2 j ^ V m

E → = 4.8 × 10 2 c o s 2 × 10 7 z - 6 × 10 15 t 2 i ^ + j ^ V m

The electric field of a plane electromagnetic wave is given by E → = E 0 i ^ c o s k z c o s ( ω t ) The corresponding magnetic field B → is then given by:

B → = E 0 c j ^ sin ⁡ k z s i n ( ω t )

B → = E 0 c j ^ cos ⁡ k z s i n ( ω t )

B → = E 0 c k ^ sin ⁡ k z c o s ( ω t )

B → = E 0 c j ^ sin ⁡ k z c o s ( ω t )

The electric field of a plane polarized electromagnetic wave in free space at time t = 0 is given by the expression E → x , y = 10 j ^ c o s 6 x + 8 z . The magnetic field B → x , z , t is given by ( c is the velocity of light.)

1 c 6 k ^ - 8 i ^ c o s 6 x + 8 z - 10 c t

1 c 6 k ^ - 8 i ^ cos 6 x + 8 z + 10 c t

1 c 6 k ^ + 8 i ^ cos 6 x + 8 z - 10 c t

1 c 6 k ^ + 8 i ^ cos 6 x - 8 z + 10 c t

Given below are two statements : Statement I : Electromagnetic waves are not deflected by electric and magnetic field. Statement II : The amplitude of electric field and the magnetic field in electromagnetic waves are related to each other as E 0 = μ 0 ε 0 B 0 . In the light of the above statements, choose the correct answer from the options given below:

Statement I is true but statement II is false

Both Statement I and Statement II are true

Statement I is false but statement II is true

Both Statement I and Statement II are false

HARD

JEE Main

IMPORTANT

Earn 100

The magnetic field of a plane electromagnetic wave is given by $\vec{B} = B_{0} \hat{i} [c o s (k z - ω t)] + B_{1} \hat{j} c o s (k z + ω t)$ , where $B_{0} = 3 \times 10^{- 5} T$ and $B_{1} = 2 \times 10^{- 6} T$ . The $RMS$ value of the force experienced by a stationary charge $Q = 10^{- 4} C$ at $z = 0$ is closest to

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Important Questions on Electromagnetic Waves

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 9th April 2019 Shift 2>Q 32

Sunlight of intensity

50 W m^{- 2}

is incident normally on the surface of a solar panel. Some part of incident energy (

25 %

) is reflected from the surface and the rest is absorbed. The force exerted on

1 m^{2}

surface area will be close to

(c = 3 \times 10^{8} m s^{- 1})

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 9th January 2019 Shift 2>Q 33

The energy associated with electric field is

(U_{E})

and with magnetic field is

(U_{B})

for an electromagnetic wave in free space. Then:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 8th April 2019 Shift 1>Q 34

A plane electromagnetic wave travels in free space along the x-direction. The electric field component of the wave at a particular point of space and time is

E = 6 V m^{- 1}

along y-direction. Its corresponding magnetic field component,

B

would be:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 8th April 2019 Shift 2>Q 35

The magnetic field of an electromagnetic wave is given by:

\vec{B} = 1.6 \times 10^{- 6} \cos (2 \times 10^{7} z + 6 \times 10^{15} t) (2 \hat{i} + \hat{j}) \frac{W b}{m^{2}}

The associated electric field will be:

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 10th April 2019 Shift 1>Q 36

The electric field of a plane electromagnetic wave is given by

\vec{E} = E_{0} \hat{i} c o s (k z) c o s (ω t)

The corresponding magnetic field

\vec{B}

is then given by:

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 10th January 2019 Shift 1>Q 37

If the magnetic field of a plane electromagnetic wave is given by (The speed of light

= 3 \times 10^{8} m s^{- 1}

)

B = 100 \times 10^{- 6} \sin [2 π \times 2 \times 10^{15} (t - \frac{x}{c})]

then the maximum electric field associated with it is:

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 10th January 2019 Shift 2>Q 38

The electric field of a plane polarized electromagnetic wave in free space at time

t = 0

is given by the expression

\vec{E} (x, y) = 10 \hat{j} c o s (6 x + 8 z)

. The magnetic field

\vec{B} (x, z, t)

is given by (

c

is the velocity of light.)

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 17 - Electromagnetic Waves>JEE Main - 12th April 2019 Shift 1>Q 39

An electromagnetic wave is represented by the electric filed

\vec{E} = E_{0} \hat{n} \sin [ω t + (6 y - 8 z)] .

Taking unit vectors in

x, y

and

z

directions to be

\hat{i}, \hat{j}, \hat{k},

the directions of propagations

\hat{s},

is:

The magnetic field of a plane electromagnetic wave is given by B→=B0i^coskz-ωt+B1j^coskz+ωt, where B0=3×10–5 T and B1=2×10–6 T. The RMS value of the force experienced by a stationary charge Q=10–4 C at z=0 is closest to

Important Questions on Electromagnetic Waves

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