MEDIUM

JEE Advanced

IMPORTANT

Earn 100

The magnetic force on a moving charge is $\vec{F} = q \vec{v} \times \vec{B}$ . Here $q$ is electric charge on particle, $v$ is velocity of the particle and $B$ is magnetic field.

A charged particle of charge $1 C$ moving with a velocity $(\hat{i} + \hat{j} - \hat{k}) m s^{- 1}$ in a magnetic field $B = (2 \hat{i} - \hat{j} + 4 \hat{k}) T$ .

Choose the correct option(s).

50% studentsanswered this correctly

Important Questions on Vectors

MEDIUM

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 1

According to Newton's second law of motion, the resultant force on a particle is in the direction of acceleration of the particle.

Question Image

Two forces $F_{1}$ and $F_{2}$ are acting on a particle as shown in the figure. The acceleration of the particle is along $x$ -axis. Find the value of $F_{1}$ (in newton).

EASY

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 2

In vector

\vec{A}

and

\vec{B}

be respectively equal to

3 \hat{i} - 4 \hat{j} + 5 \hat{k}

and

2 \hat{i} + 3 \hat{j} - 4 \hat{k}

. The unit vector parallel to

\vec{A} + \vec{B}

\frac{1}{\sqrt{27}} (5 \hat{i} - a \hat{j} + \hat{k})

. Find the value of

a

MEDIUM

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 5

The two-point charges

q_{1}

and

q_{2}

are placed at

(0, 0, 0)

and

(1, 2, 2) m

, respectively. They repel each other with a force of

3 N

. The force on the

q_{2}

due to

q_{1}

\vec{F_{21}} = (x \hat{i} + y \hat{j} + z \hat{k}) N

. Find the value of

x + y + z

MEDIUM

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 6

Four forces are acting on a particle. One force of magnitude

3 N

is directed upward, another is directed

37 °

East of North having the magnitude

5 N

, third is directed in South-West direction is of magnitude

4 \sqrt{2} N

and fourth force is

\sqrt{5 n} N

. If the particle is in equilibrium. Find the value of

n

EASY

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 7

\vec{a} = 2 \hat{i} - 3 \hat{j} + \hat{k}

and

\vec{b} = x \hat{i} + \hat{j} + \hat{k}

are mutually perpendicular, Find the value of

x

MEDIUM

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 8

Find the volume of parallelepiped

(in m^{3})

whose edges are represented by

a = (2 \hat{i} - 3 \hat{j} + 4 \hat{k}) m

b = (\hat{i} + 2 \hat{j} - \hat{k}) m

and

c = (3 \hat{i} - \hat{j} + 2 \hat{k}) m

MEDIUM

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 9

\vec{A} = 2 \hat{i} - \hat{j} + \hat{k}

\vec{B} = \hat{i} + 2 \hat{j} - 3 \hat{k}

and

\vec{C} = 3 \hat{i} - y \hat{j} + 5 \hat{k}

are coplanar. Find the value of

y

EASY

JEE Advanced

IMPORTANT

PHYSICS For Joint Entrance Examination JEE (Advanced) Mechanics I>Chapter 3 - Vectors>Exercises>Q 10

A force of

1000 N

in a particular direction must be applied to a block. For same reason. It is not possible to apply the force in that direction but two forces can be applied to

30^{°}

and

45^{°}

on either side of it in the same plane containing the given force. If the ratio of magnitude of forces as

\sqrt{n}

. Find the value of

n

The magnetic force on a moving charge is F→=qv→×B→. Here q is electric charge on particle, v is velocity of the particle and B is magnetic field. A charged particle of charge 1 C moving with a velocity i^+j^-k^ m s-1 in a magnetic field B=2i^-j^+4k^ T. Choose the correct option(s).

Important Questions on Vectors

Learn and Prepare for any exam you want !