MEDIUM
JEE Main
IMPORTANT
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The magnitude and direction of the current in the circuit shown will be:
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Important Questions on Current Electricity

MEDIUM
JEE Main
IMPORTANT

The variation of terminal potential difference V with current flowing through as cell is as shown

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The emf and internal resistance of the cell are

MEDIUM
JEE Main
IMPORTANT
Two cells each of emf E and internal resistance r1 and r2 respectively are connected in series with an external resistance R. The potential difference between the terminals of the first cell will be zero when R is equal to
MEDIUM
JEE Main
IMPORTANT

In the given circuit find reading of ammeter (in A) when capacitor has attained steady state. (Approximate the answer to the nearest integer)

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MEDIUM
JEE Main
IMPORTANT

One of the circuits for the measurement of resistance by potentiometer is shown. The galvanometer is connected at point A and zero deflection is observed at length PJ=30 cm. In second case the secondary cell is changed. Take ES=10 V and r=1Ω in 1st reading and ES=5 V and r=2Ω in 2nd  reading. In second case, the zero deflection is observed at length PJ=10 cm. What is the resistance R (in ohm)?

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EASY
JEE Main
IMPORTANT

In the potentiometer circuit of the figure, when the key K is inserted, balanced length is found to be 20 cm for R=10 Ω and 24 cm for R=20 Ω. The balanced length if key K is taken out will be,

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EASY
JEE Main
IMPORTANT
The maximum current in a galvanometer can be 10 mA. It's resistance is 10Ω. To convert it into an ammeter of 1 Amp. a resistor should be connected in