At t = 0, three particles A, B and C are located at the origin of the coordinate system. Then they start moving simultaneously, A moves with a constant velocity of 3 i ^ (m/s) and B moves under a constant acceleration of 2 k ^ (m/s 2 ) with an initial velocity of 8 j ^ (m/s). Particle C moves with constant velocity v 0 in such a way that B and C collide at t = 4s. Then,

position vector of location where two particles collide is 16 i ^ + 32 k ^

both (v 0 is 8 j ^ + 4 k ^ ) and (Position vector of location where two particles collide is 16 i ^ + 32 k ^ ) are correct

it is not possible that B and C collide with each other for any value of v 0

The trajectory of a projectile near the surface of the earth is given as y = 2 x - 9 x 2 . If it were launched at an angle θ 0 with speed v 0 then g = 10 m s - 2 :

θ 0 = cos - 1 1 5 and v 0 = 5 3 m s - 1

θ 0 = cos - 1 2 5 and v 0 = 3 5 m s - 1

θ 0 = sin - 1 1 5 and v 0 = 5 3 m s - 1

θ 0 = sin - 1 2 5 and v 0 = 3 5 m s - 1

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IMPORTANT

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The magnitude of scalar product of two vectors is $8$ and of vector product is $8 \sqrt{3}$ . The angle between them is :-

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Important Questions on Motion in a Plane

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IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 2

A flag on a bus is fluttering in north direction and wind is blowing in east direction. Then which of the following will be true.

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 3

\vec{A}

and

\vec{B}

denote the sides of a parallelogram and its area is

\frac{1}{2} A B

(

A

and

B

are magnitude of

\vec{A}

and

\vec{B}

respectively), the angle between

\vec{A}

and

\vec{B}

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IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 1

Assertion: Whenever a particle is moving with acceleration, velocity of particle increases.

Reason: Acceleration of particle is defined as rate of change of velocity with respect to time.

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 2

A particle has initial velocity

(2 \hat{i} + 3 \hat{j})

and acceleration

(0.3 \hat{i} + 0.2 \hat{j})

. The magnitude of velocity after 10 seconds will be

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 3

A particle is moving with a velocity

\vec{v} = K (y \hat{i} + x \hat{j}),

where

K

is a constant.

The general equation for its path is:

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IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 4

At t = 0, three particles A, B and C are located at the origin of the coordinate system. Then they start moving simultaneously, A moves with a constant velocity of 3 $\hat{i}$ (m/s) and B moves under a constant acceleration of 2 $\hat{k}$ (m/s²) with an initial velocity of 8 $\hat{j}$ (m/s). Particle C moves with constant velocity v₀ in such a way that B and C collide at t = 4s.
Then,

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IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 5

A particle moves in such a way that its position as a function of time is given by

\vec{r} = \hat{i} + 4 t^{2} \hat{j} + t \hat{k}

, where

r

is in

(m)

and

t

is in

(s)

. Then the trajectory of the particle is

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IMPORTANT

Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 4 - Motion in a Plane>Exercise>Q 6

A particle moves in the

x - y

plane with velocity

v_{x} = 8 t - 2

and

v_{y} = 2

. If it passes through the pointy

x = 14

and

y = 4

t = 2 s

, find the equation (

x - y

relation) of the path

The magnitude of scalar product of two vectors is 8 and of vector product is 83. The angle between them is :-

Important Questions on Motion in a Plane

Learn and Prepare for any exam you want !

The magnitude of scalar product of two vectors is $8$ and of vector product is $8 \sqrt{3}$ . The angle between them is :-