EASY
JEE Main/Advance
IMPORTANT
Earn 100

The marks of some students were listed out of a maximum 100. The standard deviation of marks was found to be 9. Subsequently the marks raised to a maximum of 150 and standard deviation of new marks was calculated. The new standard deviation

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Important Questions on Statistics

HARD
JEE Main/Advance
IMPORTANT
Find the arithmetic mean of C02n+1, C12n+1, ..2n+1Cn
MEDIUM
JEE Main/Advance
IMPORTANT

Following is the record of goals scored by team A in football session

Numbers of goals scored 0 1 2 3 4
Numbers of match is 1 9 7 5 3

for team B mean number of goals scored per match was 2 goals with standard deviation 1.25. The team which is more consistent

HARD
JEE Main/Advance
IMPORTANT
The mean of two samples of sizes 200 and 300 were found to be 25, 10, respectively. Their standard deviations were 3 and 4 respectively. Find the variance of combined sample of size 500
MEDIUM
JEE Main/Advance
IMPORTANT
The first of the two samples have 100 items with mean 15 and S.D. 3. If the whole group has 250 items with mean 15.6 and S.D.=13.44 then S.D. of the second group is
HARD
JEE Main/Advance
IMPORTANT
The average marks of 10 students in a class was 60 with standard deviation 4. While the average marks of other 10 students was 40 with a standard deviation 6. If all the 20 students are taken together, their standard deviation will be
HARD
JEE Main/Advance
IMPORTANT
The mean and variance of 5 observations of an experiment are 4 and 5.2, respectively. From these observations three are 1, 2 and 6 and λ=x1-x2+8 where x1 & x2 are remaining observations, then number of solution of equation 10-x2-2x=λ are
HARD
JEE Main/Advance
IMPORTANT
The mean and variance of 10 numbers were calculated as 11.3 and 3.3, respectively. It was subsequently found that one of the number was misread as 10 instead of 12. How does the variance change?
HARD
JEE Main/Advance
IMPORTANT

STATEMENT-1 : i=19xi-8=9 and i=19xi-82=45, then S.D. of x1, x2, , x9 is 2

STATEMENT-2 : S.D. is independent of change of origin