The mass of Co 27 57 : 56 . 936296 u ; Fe 26 57 : 56 . 935399 u are given. Two possible nuclear reactions are proposed (i) Co 27 57 → Fe 26 57 + e + 1 0 + v (positron emission) (ii) Co 27 57 + e - 1 0 → Fe 26 57 + v ( K -shell capture) of these two reactions,

(i) is not spontaneous but (ii) is spontaneous

(i) is spontaneous but (ii) is not spontaneous

(i) is spontaneous as well as (ii) is spontaneous

(i) is not spontaneous as well as (ii) is not spontaneous

The mass of Co 27 57 : 56 . 936296 u ; Fe 26 57 : 56 . 935399 u are given. Two possible nuclear reactions are proposed (i) Co 27 57 → Fe 26 57 + e + 1 0 + v (positron emission) (ii) Co 27 57 + e - 1 0 → Fe 26 57 + v ( K -shell capture) of these two reactions,

(i) is not spontaneous but (ii) is spontaneous

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The mass of ${}_{27}^{57}{Co} : 56.936296 u; {}_{26}^{57}{Fe} : 56.935399 u$ are given. Two possible nuclear reactions are proposed
(i) ${}_{27}^{57}{Co} \to {}_{26}^{57}{Fe} + {}_{+ 1}^{0}e + v$ (positron emission)
(ii) ${}_{27}^{57}{Co} + {}_{- 1}^{0}e \to {}_{26}^{57}{Fe} + v$ ( $K$ -shell capture)

of these two reactions,

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Important Questions on Atoms and Nuclei

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

The mass-defect in a nuclear fusion reaction is

0.3

per cent. The amount of energy released in one

kg

of fusion reaction is

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

What is the binding energy of ${}_{14}^{29}S i$ whose atomic mass is $28.976495 u$

Mass of proton $= 1.007276 u$

Mass of neutron $= 1.008664 u$

(Neglect the electron mass) (Assume $1 u = 931.5 MeV$ )

MEDIUM

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

A nucleus

X

emits a

β

-particle to produce a nucleus

Y

. If their atomic masses are

M_{x}

and

M_{y}

respectively, then the maximum energy of the

β

-particle emitted is (where,

m_{e}

is the mass of an electron and

c

is the velocity of light)

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

The binding energy per nucleon of

{{}_{8}C}^{12} = 12.0038 amu

, mass of neutron

= 1.00898 amu

and mass of proton

= 1.007599 amu

HARD

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

Consider the nuclear fission,

{Ne}^{20} \to 2 {He}^{4} + C^{12}

. Given that the binding energy/nucleon of

{Ne}^{20}, {He}^{4}

and

C^{12}

are

8.03 MeV, 7.86 MeV

, respectively. Identify the correct statement:

MEDIUM

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

The ratio of the binding energies of three nuclei is

1 : 4 : 9

. If the ratio of their nuclear radii is

1 : 2 : 3

, the nuclei in the decreasing order of the stability can be arranged as

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

If the binding energy of

N^{14}

7.5 MeV

per nucleon and that of

N^{15}

7.7 MeV

per nucleon, then the energy required to remove a neutron from

N^{15}

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

Four nuclei of an element undergo fusion to form a heavier nucleus, with release of energy. Which of the two the parent or the daughter nucleus would have higher binding energy per nucleon ?

HARD

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

The electrostatic energy of

Z

protons uniformly distributed throughout a spherical nucleus of radius

R

is given by,

E = \frac{3}{5} \frac{Z (Z - 1) e^{2}}{4 π ε_{0} R}

. The measured masses of the neutron,

{}_{1}^{1}H, {}_{7}^{15}N and {}_{8}^{15}O

are

1.008665 u

1.007825 u, 15.000109 u and 15.003065 u

respectively. Given that the radii of both the

{}_{7}^{15}N and {}_{8}^{15}O

nuclei are same,

1 u = 931.5 MeV c^{- 2}

(

c

is the speed of light) and

\frac{e^{2}}{(4 π ϵ_{0})} = 1.44 MeV fm

. Assuming that the difference between the binding energies of

{}_{7}^{15}N a n d {}_{8}^{15}O

is purely due to the electrostatic energy, the radius of either of the nuclei is

(1 fm = 10^{- 15} m)

MEDIUM

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

Find the Binding energy per nucleon for

{}_{50}^{120}{Sn}

. Mass of proton

m_{p} = 1.00783 u

, mass of neutron

m_{n} = 1.00867 u

and mass of tin nucleus

m_{Sn} = 119.902199 u

. (take

1 u = 931 MeV

)

MEDIUM

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

From the given data, the amount of energy required to break the nucleus of aluminium ${}_{13}^{27}{Al}$ is __________ $x \times 10^{- 3} J$ .

Mass of neutron $= 1.00866 u$
Mass of proton $= 1.00726 u$
Mass of Aluminium nucleus $= 27.18846 u$
(Assume $1 u$ corresponds to $x J$ of energy)
(Round off to the nearest integer)

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

The binding energy per nucleon of

{}_{5} B^{10}

8.0 MeV

and that of

{}_{5} B^{11}

7.5 MeV .

The Energy required to remove a neutron from

{}_{5} B^{11}

is (mass of electron and proton are

9.11 \times 10^{- 31} kg

and

1.67 \times 10^{- 27} kg

)

MEDIUM

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

A nucleus with mass number

240

breaks into two fragments each of mass number

120,

the binding energy per nucleon of unfragmented nuclei is

7.6 MeV

while that of fragments is

8.5 MeV

. The total gain in the binding energy in the process is :

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

In a certain mass spectrometer, an ion beam passes through a velocity filter consisting of mutually perpendicular fields E and B. The beam then enters a region of another magnetic field

B^{'}

, perpendicular to the beam. The radius of curvature of the resulting ion beam is proportional to

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

Which of the following statement is correct?

MEDIUM

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

What is pair production?

HARD

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

Explain the processes of nuclear fission and nuclear fusion by using the plot of binding energy per nucleon

(B E / A)

versus the mass number

A

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

You are given that Mass of

{}_{3}^{7}{Li} = 7.0160 u,

Mass of

{}_{2}^{4}{He} = 4.0026 u

and Mass of

{}_{1}^{1}{He} = 1.0079 u

. When

20 g

{}_{3}^{7}{Li}

is converted into

_{2}^{4} He

by proton capture, the energy liberated, (in

kWh

), is: [Mass of nucleon

= 1 GeV / c^{2}

]

EASY

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

If the binding energy of the electron in a hydrogen atom is

13.6 eV

, the energy required to remove the electron from the first excited state of

{Li}^{+ +}

is :

MEDIUM

Physics>Modern Physics>Atoms and Nuclei>Binding Energy and Its Calculation

Two deuterons undergo nuclear fusion to form a Helium nucleus. The energy released in this process is (given binding energy per nucleon for deuteron

= 1.1 MeV

and for helium

= 7.0 MeV

)

The mass of Co2757:56.936296u ; Fe2657:56.935399u are given. Two possible nuclear reactions are proposed (i) Co2757→Fe2657+e+10+v (positron emission) (ii) Co2757+e-10→Fe2657+v (K-shell capture) of these two reactions,

Important Questions on Atoms and Nuclei

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